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3 years ago

Yooo please help me w dis!! marking brainiest answer!!

Mathematics

1 answer:

leonid [27]3 years ago

3 0

Answer:

${4}^{x + 7}$

Step-by-step explanation:

since it is an exponential graph shifted 7units to the left would be

${4}^{x + 7}$

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Express the following fraction in simplest form using only positive exponents.

ElenaW [278]

Answer:

32h^7

Step-by-step explanation:

3 0

3 years ago

line pass through the line (-3, -7.5)tahila determined that the equation of line n is y=0.5x explain the error tahila made while

Tasya [4]

The equation of the line will be (assuming the y-intercept equal to zero):

y = 2.5*x

<h3>What is Tahila's mistake?</h3>

We know that we have a linear equation of the form:

y = a*x + b

Such that we know that the line passes through (-3, -7.5), notice that the proposed equation is:

y = 0.5*x

If you evaluate that in -3, you get:

y = 0.5*-3 = -1.5

So this line does not pass through (-3, -7.5).

If we assume that b = 0 in the linear equation, then we can find the value of a as:

-7.5 = a*-3

a = 7.5/3 = 2.5

Then the linear equation is:

y = 2.5*x

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

4 0

2 years ago

Plz help answer fast

spayn [35]

Answer:

d because it does not looks somlar

5 0

2 years ago

Read 2 more answers

Help me with these questions

Elena L [17]

Answer: a = 4, b = 163,422

Step-by-step explanation:

$P = P_{0} e^{kt}$ P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 (converted 21% into a decimal)

t = 36 yrs (2006 - 1970)

$P = P_{0} e^{kt}$ need to solve for P₀

$7003 = P_{0} e^{(.21)(36)}$

$7003 = P_{0} e^{7.56}$

7003 = P₀ (1920)

$\frac{7003}{1920} = P_{0}$

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 (converted 21% into a decimal)

t = 15 yrs (2021 - 2006)

$P = P_{0} e^{kt}$ need to solve for P₀

$P = 7003 e^{(.21)(15)}$

$P = 7003 e^{3.15}$

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

*************************************************************

Answer: 2, -1

Step-by-step explanation:

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0 or x + 1 = 0

x = 2 or x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴ or e¹ = e¹

TRUE TRUE

*****************************************

Answer: 0 = ln 1

Step-by-step explanation:

$e^{-10} = \frac{1}{e^{10}}$

$ln(e^{-10}) = ln(\frac{1}{e^{10}})$

-10 = ln 1 - 10 log rules say division is subtraction

0 = ln 1

5 0

3 years ago

(04.01)The Baldwin family walked 4/5 of a mile in 4/9 of an hour. What is their unit rate in miles per hour?

sertanlavr [38]

Hello!

Since we know how much they walked in 4/9 of an hour, we will divide 4/5 by 4/9 to get 4/9 to one.

$\frac{4}{5}$ ÷ $\frac{4}{9}$ = $\frac{36}{20} = \frac{9}{5}$

They went 1 4/5 mph or 1.8 mph.

I hope this helps!

7 0

3 years ago

Read 2 more answers