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Ann [662]
3 years ago
8

You think you’ve sprained your ankel

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0
No ankle nope definitely not serious
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What is the value of x?<br> x = [ ? ]
Mnenie [13.5K]

Answer:

Step-by-step explanation:

The tangent to the angle makes an angle of 90° with the radius.

The interior angle of the equilateral triangle is 60, so that leaves 90-60 = 30° for the remaining angle with the tangent.

By the exterior angle theorem, 30°+x° = 60° (interior angle of the equilateral triangle), therefore

x = 60-30 = 30°.

4 0
3 years ago
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An online music store is offering a promotion. When you spend $30 or more, you receive 3 songs for free. You Buy an album for $1
Lisa [10]

Answer:

need to spend $18 more in addition to $12

Step-by-step explanation:

Given: According to online music store, if you spend $30 or more, you receive 3 songs for free

To find: How much more money need to be spend in addition to $12 to receive three free songs

Solution:

Let x denotes amount to be spend in addition to $12 to receive three free songs

According to question,

x+12\geq 30\\x\geq 30-12\\x\geq 18

3 0
3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

6 0
3 years ago
what types of problems can be solved using the greatest common factor and what types of problems can be solved using the least c
Arisa [49]
The first one is finding the square root of things I believe and I'm not sure about the second one sorry
7 0
3 years ago
A kangaroo hopped \dfrac13 3 1 ? of the distance to the lake with her baby in her pouch. She hopped the remaining 70407040 yards
kogti [31]

Answer:

6 miles.

Step-by-step explanation:

Let x be the total distance hoped by Kangaroo to the lake.

We have been given that a kangaroo hopped 1/3 of the distance to the lake with her baby in her pouch.

She hopped the remaining 7040 yards without her baby in her pouch. This means that 2/3 of total distance (x) is 7040. We can represent this information in an equation as:

\frac{2}{3}*x=7040

Let us solve for x by multiplying both sides of our equation by 3/2.

\frac{3}{2}*\frac{2}{3}*x=\frac{3}{2}*7040

x=3*3520

x=10560

Therefore, the total distance hoped by the kangaroo is 10560 yards.

1 mile = 1760 yards

Let us convert this distance in miles by dividing 10560 yards by 1760.

\text{The kangaroo hoped}=\frac{10560\text{ yards}}{\frac{1760\text{ yards}}{\text{Mile}}}

\text{The kangaroo hoped}=\frac{10560\text{ yards}}{1760}\times \frac{\text{ Mile}}{\text{ yards}}

\text{The kangaroo hoped}=\frac{10560}{1760}\times\text{ Mile}

\text{The kangaroo hoped}=6\text{ Miles}

Therefore, the kangaroo hoped 6 miles to the lake.

3 0
3 years ago
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