Answer:
The domain of P is given by,
{n | n ∈ N, 2 ≤ n ≤ 12}
Step-by-step explanation:
A perfect die is perfectly cubic in shape with one of the integers 1,2,3,4, 5 or 6 in each of it's 6 faces and the digits on any two faces are different.
Now, two dice are rolled and P(n) models the probability of the event that the sum on the faces of the two dice is n.
Hence, the domain of P is given by,
{n | n ∈ N, 2 ≤ n ≤ 12}
Greetings from Brasil...
Here we have an indeterminacy 0/0
We can change variable or rationalize.......
Let's rationalize
{[√(X + 4) - 2]/X} · {[√(X + 4) + 2]/[√(X + 4) + 2]} = 1/[√(X + 4) + 2]
So, the limit will be 1/4
"n choose k" gives you the number of possible unique combinations...
n!/(k!(n-k)!)
n=number of elements to choose from and k=the number of elements that you choose...in this case:
7!/[2!(7-2)!]
7!/[2!5!]
21
There are 21 possible different two question combinations that she can pick.
D , none of the above!!!!
Answer:
Whoa, that's a lot to answer...
15. 30000=500x
16. y=58x+5
in 16, the total cost is y, so y has to be in 1 side for itself. and we need to add the amount of tickets and the fee (5$). So we get that equation.
