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Leviafan [203]
3 years ago
6

--12 + 8x < -44 i need help​

Mathematics
1 answer:
tigry1 [53]3 years ago
7 0
The answer to this problem is x<-4
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jek_recluse [69]

Answer:

<u>2) Vertical scale does not begin with zero</u>

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2 years ago
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Another question, what is 94939423^2 have fun!
Bas_tet [7]
The answer is 9,013,494,039,572,928 :)
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Find c. Round to the nearest tenth
sergeinik [125]

Answer:

c = <u>0.5 cm</u>

Step-by-step explanation:

Using the Sine rule in the triangle, then

=  ( cross- multiply )

c × sin105° = 2 × sin15° ( divide both sides by sin105°

c =  ≈ 0.5 cm ( to the nearest tenth )

8 0
3 years ago
Reflect triangle ABC over the x-axis. Then translate the new triangle 5 units to the left. What are the coordinates of the verti
makvit [3.9K]

Hi there!

The answer to your question is B my explanation is below

The coordinates of the vertices of the final image will be:

A''(-6, 8), B''(-7, -2), and C''(0, -2)

Hence, option (B) is true.

Step-by-step explanation:

Given the triangle with the vertices

A(-1, -8)B(-2, 2)C(5, 2)We know that when we reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate reverses its sign.

Thus,

The rule of reflection across the x-axis:

(x, y) → (x, -y)

so

A(-1, -8) → A'(-1, -(-8)) = A'(-1, 8)

B(-2, 2) → B'(-2, -2) = B'(-2, -2)

C(5, 2) → C'(5, -2) = C'(5, -2)

Then, translate the new triangle 5 units to the left

Rule of translating 5 units to the left

(x, y) → (x-5, y)

so

A'(-1, 8) → A''(-1-5, 8) = A''(-6, 8)

B'(-2, -2) → B''(-2-5, -2) = B''(-7, -2)

C'(5, -2) → C''(5-5, -2) = C''(0, -2)

Therefore, the coordinates of the vertices of the final image will be:

A''(-6, 8), B''(-7, -2), and C''(0, -2)

Hence, option (B) is true.

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3 years ago
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Last one I have to do!
Maksim231197 [3]

Answer:

one Square wide and 5 high

Step-by-step explanation:

5 0
3 years ago
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