The sum of four times a number and eight is between zero and twelve
2 answers:
Answer:
Step-by-step explanation:
The sum of four times a number and eight is between zero and twelve
For example : x is between a and b can be written as a<x<b
Now we frame inequality for the given statement
Sum of four times a number and eight
LEt the unknown number be x
four times a number is 4x
Sum of 4x and 8 is
4x+8 lies between 0 and 12. So the inequality becomes
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Solution: The dilation of gk by a scale factor of 2 centered at (-2,-4) is and
.
Explanation:
It is given that the scale factor is 2 and center of dilation is (-2,-4).
If the center of dilation is (a,b) with scale factor k, then the dilation of a point P(x,y) is determined by the given formula.
.....(1)
To find the g' substitute x=0, y=0, a=-2, b=-4 and k=2 in equation (1).
To find the k' substitute x=4, y=4, a=-2, b=-4 and k=2 in equation (1).
Therefore, the dilation of gk by a scale factor of 2 centered at (-2,-4) is and
.