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qwelly [4]
3 years ago
10

The first term in the sequence below is 2.

Mathematics
1 answer:
Art [367]3 years ago
3 0
-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9

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lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

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Hi if y’all would like to help I would rlly appreciate it :) also +30 points if u can help meeeee thanks!
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Answer:

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Answer:

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Step-by-step explanation:

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