3 years ago

The first term in the sequence below is 2.

1 answer:

3 0

-7n + 9 because the common difference is -7, so you have -7n, and then by plugging in the term numbers and the values, you find out that you need to add 9 to the -7n, so the answer is -7n + 9

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<img src="https://tex.z-dn.net/?f=%28-3x%5E2y%29%5E%7B4%7D" id="TexFormula1" title="(-3x^2y)^{4}" alt="(-3x^2y)^{4}" align="absm

Valentin [98]

Answer:

errr polynomials ahaha

so basically we can multiply the power outside of the parantheses with the exponents on the inside:

$-3x^{2*4} y^{1*4}$

this will give us:

-3x^8y^4

we also unfortunately, have to use the power on the coefficient -3 as well and we cant just MULTIPLY -3 by 4, we are going to have to multiply -3 with -3 4 TIMES(anytime we see a coefficient we MUST multiply the coefficient by itself according to the number outside of the parantheses)

so:

-3*-3*-3*-3=81

final expression

$81x^{8}y^{4}$