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Svet_ta [14]
3 years ago
11

What is the value of (f-g)(7)?f(x)=2+x;g(x)=x^2+5(f-g)(7)=[1]​

Mathematics
1 answer:
Sav [38]3 years ago
8 0

Answer:

Alright so on this type of problem you just perform the operation they ask for, which in this case is subtraction.  

Your first step will be to set up the problem:

f(x) - g(x)

Next you will substitute in your values:

(2x + 1) - (x2 - 7)

The easiest way to do the subtraction problems is to distribute your negative into your second set of parenthesis, so your expression would become:

2x + 1 - x2 + 7

Then combine your like terms:

2x - x2 + 8

Lastly put your expression in standard form (highest exponent to lowest)

-x2 + 2x + 8

Hope this helped!

Step-by-step explanation:

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Area of the figure??
8_murik_8 [283]

Answer:

28.5 sq. meters

Step-by-step explanation:

6x3=18 + 6 x 2 divided by 2=6 + 3x3 divided by 2=4.5

=28.5

8 0
3 years ago
Find the value of 5x-6 given that 2x-7=9​
erik [133]

Answer:

34

Step-by-step explanation:

Given that

2x - 7 = 9 ← solve for x

Add 7 to both sides

2x = 16 ( divide both sides by 2 )

x = 8

Substitute x = 8 into 5x - 6

5x - 6 = (5 × 8) - 6 = 40 - 6 = 34

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I hope this helps you

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3 years ago
What is the value of the expression 10(6 + 5)² when b = 3?
SashulF [63]

10(3+5)^2

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3 0
2 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
2 years ago
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