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Gnesinka [82]
3 years ago
12

Hjhhbhjdjjdjdjjsjejsjsi

Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:sufwubfwjbfuiqwnuednfubqw cjbew

Step-by-step explanation: wejfuncuwebfucwbrpubfwuefb38248237r8

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Okay so this is for my math homework that I wasn't able to do earlier.
WITCHER [35]

What is the question?????

4 0
3 years ago
Help plssssssssssssssssssssssssssss
Elenna [48]

Answer:

Step-by-step explanation:

Substituting x and y values into the equations, we can get the equation

y = 7 -3x

slope: -3

8 0
3 years ago
Read 2 more answers
You have a list of 1,000 random, normally distributed numbers with a mean of 20 and a standard deviation of 3. Which statement i
Ludmilka [50]
You're going to have to work out the z-scores of both values in each option and see if it makes sense.

n = m + sz

The mean is 20 and the standard deviation is 3.

So let's find try the z-scores of the outer range values and determine their probabilities:

from 14-20:

n = m + sz
20 = 20 + 3z and 14 = 20 + 3z
0 = 3z and -6 = 3z
z = 0 and z = -2

So now using a z-score table, such as the one below, find the probabilities.

z = 0 is easy, it's 0.5
z = -2 is 0.02275

Subtract the smaller from the larger to get the probability of getting in the range:

0.5 - 0.02275 = 0.47725 (so times 1000, you get 477.25, which is not about 340, so this option is wrong)
---
Now trying option 2, from 17-29:

n = m + sz
29 = 20 + 3z and 17 = 20 + 3z
9 = 3z and -3 = 3z
z = 3 and z = -1

0.99865 - 0.158655 = 0.839995 (not 680, so not the answer)
---
Now trying option 3, from 20-23:

n = m + sz
23 = 20 + 3z and 20 = 20 + 3z
3 = 3z and 0 = 3z
z = 1 and z = 0

0.841345 - 0.5 = 0.341345 (close to 340, so is your answer)
8 0
3 years ago
$3.00/hour = ____ cents/minute? a. 3.4 b. 5 c. 1.8 d. 300
Artist 52 [7]
1$ = 100 cents,    1 hour = 60 minutes

$3.00/hour =  (3*100) cents / (1*60)minutes
 
                   =  300 cents/60 minutes
 
                   = 5 cents/minute

Option b.
8 0
3 years ago
Read 2 more answers
x2 + 2x + 7 = 21 The number of positive solutions to this equation is . The approximate value of the greatest solution to the eq
barxatty [35]
I need help and no one is helping me
8 0
3 years ago
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