K = 917 + 6(w + h - a)
k = 1925
w = 119
a = 25
1925 = 917 + 6(119 + h - 25) =
1925 = 917 + 6(h + 94)
1925 = 917 + 6h + 564
1925 = 1481 + 6h
1925 - 1481 = 6h
444 = 6h
444/6 = h
74 = h........she is 74 inches tall
Tony's current scores are 22 and 25.
Let x = Tony's next score.
To make the lower required score of 27,
(x + 22 + 25)/3 = 27
x = 81 - 47 = 34
To make the upper required score of 32,
(x + 22 + 25)/3 = 32
x = 96 - 47 = 49
Answer:
Tony should score between 34 and 49
The given matrix equation is,
.
Multiplying the matrices with the scalars, the given equation becomes,
![\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1.5x%269%5C%5C12%266%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dy%264y%5C%5C3y%262y%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20%20)
Adding the matrices,
![\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right] \\](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1.5x%2By%269%2B4y%5C%5C12%2B3y%266%2B2y%5Cend%7Barray%7D%5Cright%5D%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5C%20)
Matrix equality gives,

Solving the equations together,

We can see that the equations are not consistent.
There is no solution.
It’s wrong.
The surface area means the area of the outside of the cube.
The area of a square is just width x height. And we are told one of the sides is 5.
A square has all equal sides. So what’s 5x5? then times that by the number of squares
I’ll put the answer in the comments