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Charra [1.4K]
1 year ago
11

Please please please help

Mathematics
1 answer:
Ludmilka [50]1 year ago
7 0

Answer:r=14°

Step-by-step explanation:

(5r-5)°+ (8r+3)°=180

(Sum of angles on a straight line =180°)

Collect like terms

5r+8r-5+3=180

13r-2=180

13r=180+2

13r=182

r=182/13

r=14°

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Joe has read ​30 % of a book. He has 63 more pages to finish. How many pages are there in the​ book?
meriva

Answer:

90 pages

Step-by-step explanation:

30% complete

70% to go = 63 pages

t = total number of pages

0.7t = 63

∴ t = ⁶³/₀.₇

⁶³/₀.₇ = 90

4 0
2 years ago
If the polynomial
erik [133]

Answer:

  • (C) - x

Step-by-step explanation:

<u>Given polynomial:</u>

  • x¹⁹ + x¹⁷ + x¹³ + x⁷ + x⁵ + x³

<u>Group as follows:</u>

  • (x¹⁹ + x¹⁷) + (x¹³ + x¹¹) + (x⁷ + x⁵) + (x³ + x) - x =
  • x¹⁷(x² + 1) + x¹¹(x² + 1) + x¹⁵(x² + 1) + x(x² + 1) - x

As we see all terms have (x² + 1) as factor apart from the last one.

It means the remainder is - x

Correct choice is C

3 0
2 years ago
Please help will mark brainleist<br>Hiiii
KATRIN_1 [288]
The one the blue is on! Hope that helped
8 0
2 years ago
Read 2 more answers
Which of the following is a like radical to mc001-1.jpg?
mixer [17]
You haven't provided the expression or the choices, therefore, I cannot provide an exact answer.
However, I'll try to help you understand the concept so that you can solve the question you have

Like radicals are characterized by the following:
1- They both have the same root number (square root, cubic root , ...etc)
2- They both have the same radicand (meaning that the expression under the root is the same in both radicals)

Examples of like radicals:
3\sqrt{xyz} and 7\sqrt{xyz}
\sqrt[5]{x^2y} and 3\sqrt[5]{x^2y}

Check the choices you have. The one that satisfies the above two conditions would be your correct choice

Hope this helps :)
7 0
3 years ago
Read 2 more answers
the pressure, p. of a gas varies inversely with its volume, v. Pressure is measured in units of Pa. Suppose that a particular am
LekaFEV [45]

I think I know how to do it


Your equation is:

P₁V₁ = P₂V₂


You Know:

Initial:

P₁ = 84 Pa

V₁ = 336 L


New:

P₂ = ?

V₂ = 216L


Plug this into the equation:

P₁V₁ = P₂V₂

(84 Pa)(336 L) = P₂(216 L)     Divide 216 on both sides

\frac{(84Pa)(336L)}{216L}=\frac{(P_{2})(216L)}{216L}

130.6666666 = P₂    

(if your doing significant figures, you have 2 sig figs)

130 Pa = P₂


6 0
3 years ago
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