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3 years ago

What value of x makes the equation 4(5 - 7x) = 6 - 12x true?

Mathematics

1 answer:

Lemur [1.5K]3 years ago

7 0

Answer:

4(5 - 7x) = 6 - 12

20-28x=6-12x

Subtract 20 from both sides

20-28x-20=6-12x-20

Simplify

-28x=-12x-14

Add 12x to both sides

-28+12x=-12x=-12x-14+12x

Simplify

-16x=-14

Divide both sides by -16

-16/-16 = -14/-16

Anw

7/8= 0.875

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Check your answer. Is $15.75 a reasonable amount of interest? If Caroline had invested the $900 for a full year at 2% interest, the amount of interest would have been $18. Yes, $15.75 is reasonable.

Step-by-step explanation:

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3 years ago

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Neporo4naja [7]

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Alborosie

Answer: 10 or 6 I believe

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2 years ago

In △JKL, solve for x. (A)74.89 (B)30.29 (C)38.16 (D)66.73

Stels [109]

ANSWER

EXPLANATION

The acute angle given in the right triangle is 27°.

The side length adjacent to the 27° angle is 34 units.

The side length we want to find is x units, which is the hypotenuse of the right triangle.

We use the cosine ratio to obtain:

$\cos(27 \degree) = \frac{adjacent}{hypotenuse}$

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4 years ago

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A bank is trying to determine which model of safe to install. The bank manager believes that each model is equally resistant to

alexandr402 [8]

Answer:

So on this case the 95% confidence interval would be given by (-1.152;5.152).

$-1.152 < \mu_{safe1}-\mu_{safe2}$

Should we conclude that the average time it takes experts to crack the safes does not differ by model at the 5% significance level?

A) Yes, the 95% confidence interval for ?D contains 0.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution

Let put some notation

x=value for Safe 1 , y = value for Safe 2

x: 103, 90, 64, 120, 104, 92, 145, 106, 76

y: 101, 94, 58, 112, 103, 90, 140, 110, 74

The first step is calculate the difference $d_i=x_i-y_i$ and we obtain this:

d: 2, -4, 6, 8, 1, 2, 5, -4, 2

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{18}{9}=2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =4.093$

The next step is calculate the degrees of freedom given by:

$df=n-1=9-1=8$

Now we need to calculate the critical value on the t distribution with 8 degrees of freedom. The value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , so we need a quantile that accumulates on each tail of the t distribution 0.025 of the area.