Please Help!!!! Solve For L

Mathematics

2 answers:

Sonja [21]3 years ago

4 0

<h3>Given :</h3>

$\tt B = L - L a f$

L = ?

<h3>Solution :</h3>

$\tt B = L - L a f$

By taking L common from $\tt (L - L a f)$ , we get :

$\tt : \implies B = L(1 - a f)$

$\tt : \implies \dfrac{B}{(1 - a f)} = L$

$\tt : \implies L = \dfrac{B}{1 - a f}$

Hence, value of $\tt L = \dfrac{B}{1 - a f}$

julia-pushkina [17]3 years ago

4 0

Top person is correct.

You might be interested in

Helpppppppppppppppppppppppppp

Vsevolod [243]

Answer:

$x < - \frac{5}{13}$

$x \geqslant - \frac{1}{5}$

Step-by-step explanation:

↷

$- \frac{13}{16}x + \frac{3}{8} < \frac{11}{16} \\ \frac{ \: \: \: \: \: \: \: \: \: \: \: \: - \frac{3}{8 } < - \frac{3}{8} }{ \frac{ - \frac{13}{16}x }{ - \frac{13}{16} } < \: \: \: \frac{ \frac { 5}{16} }{ - \frac{ 13}{16} } } \\ \\ x < \frac{ - 5}{ \: 13}$

↷

$\frac{1}{3} \geqslant \frac{2}{9} - \frac{5}{9} x \\ \frac{ - \frac{ 2}{9} \geqslant - \frac{2}{9} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{ \frac{ \: \: \: \frac{1}{9}x }{ - \frac{ 5}{9} } \geqslant \frac{ - \frac{5}{9} }{ - \frac{5}{9} } } \\ \\ x \geqslant - \frac{1}{5}$