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3 years ago

13

Please help me, i need it right now !!

2 answers:

Vikentia [17]3 years ago

6 0

Hello my name is Ross it’s 63 stay safe

garik1379 [7]3 years ago

3 0

Answer:

Is it 63

Step-by-step explanation:

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The perpendicular bisectors of ΔPQR intersect at point A as shown in the diagram. What is the radius of the circumscribed circle

Novosadov [1.4K]

The answer to this is 9.22

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4 years ago

Why do we use a coeficient to remove the propotionality

Salsk061 [2.6K]

Constant is the scale term in proportionality. Suppose one variable is dependent on the other and one variable become twice, other becomes also twice and if one becomes half, other too becomes half., but they are two different variables which are no-where linked (like cost(money) vs quantity). Quantity and cost are two different things but they abridge a mathematical relation of proportionality. So in the mathematics to abridge these two different variables, we need something. Constant serves that purpose.

5 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

You want to purchase a pair of shoes for at least $150. You have $55 so far. You earn $10.00 per hour at your job write an inequ

VikaD [51]

55+10.00x ≥ 150 x ≥ 9.5 hours I hope that helps

7 0

3 years ago

the ordered pairs (0,-1),(1,0),(2,3),(3,8),(4,15) represent a function what is a rule that represents this function? Please help

yarga [219]

Answer:

The function rule is

$f: x\to \: {x}^{2} - 1$

Step-by-step explanation:

The given ordered pairs are (0,-1), (1,0),(2,3),(3,8),(4,15)

We can observe the following pattern.

$f(0) = {0}^{2} - 1 = - 1$

$f(1) = {1}^{2} - 1 = 0$

$f(2) = {2}^{2} - 1 = 3$

$f(3) = {3}^{2} - 1 = 8$

$f(4) = {4}^{2} - 1 = 15$

When we generalize this pattern, we obtain:

$f(x) = {x}^{2} - 1$

This is the function equation.

The function rule is

$f: x\to \: {x}^{2} - 1$

8 0

3 years ago