A 20-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the
building at 2 ?feet/second, how fast is the top of the ladder moving down when the foot of the ladder is 3 feet from the? wall?The top of the ladder is moving down at a rate of _____ ?feet/second when the foot of the ladder is 3 feet from the wall. ?(Round to the nearest thousandth as? needed.)
1 answer:
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Answer:
Equation of line 1 is 3 X - 4 Y = 20
Equation of line 2 is 3 X + 4 Y = 20
Step-by-step explanation:
Given co ordinates of points as,
( -4 , 8) and (0 , 5)
From the given two points we can determine the slop of a line
I. e slop (m) =
Or, m =
So, m =
Now equations of line can be written as ,
Y - y1 = m ( X - x1)
<u>At points ( -4 , 8)</u>
Y - 8 = (X + 4)
So , Equation of line 1 is 3 X - 4 Y = 20
<u>Again with points ( 0 , 5)</u>
Y - 5 = ( X - 0)
So, Equation of line 2 is 3 X + 4 Y = 20
Hence Equation of line 1 is 3 X - 4 Y = 20 and Equation of line 2 is 3 X + 4 Y = 20 Answer