A = L * W
A = 70
70 = L * W
P = 2(L + W)
P = 34
34 = 2(L + W)
34/2 = L + W
17 = L + W
17 - W = L
70 = L * W
L = 17 - W
70 = W(17 - W)
70 = -W^2 + 17W
W^2 - 17W + 70 = 0
(W - 10)(W - 7) = 0
W - 10 = 0 L = 17 - 10
W = 10 L = 7
W - 7 = 0 L = 17 - 7
W = 7 L = 10
so either the width is 10 meters and the length is 7 meters OR the width is 7 meters and the length is 10 meters
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
Answer:
a and c
Step-by-step explanation:
because its a 3rd demenshion sphere