Answer:
Cesar will be doing 15 research reports during the school year.
Step-by-step explanation:
Given:
Number of research report completed = 3
Percentage of the report completed for school year = 20%
We need to find total number of research report completed during school year.
Solution:
Let the total number of research report completed during school year be 'x'.
Now we can say that;
Number of research report completed is equal to Percentage of the report completed for school year multiplied by total number of research report completed during school year and then divided by 100.
framing in equation form we get;
Dividing both side by 0.2 we get;
Hence Cesar will be doing 15 research reports during the school year.
Answer:
91
Step-by-step explanation:
Todd’s average score for six tests = 92.
The sum of two of her test = 188
First, we need to find the total score for the six test. This given below:
Average = sum of all test / number of test
sum of all the test = average x number of test
average score for six tests = 92.
Number of test = 6
Sum of all the Tests = 92 x 6 = 552
Sum of four test = sum of all the test — sum of two test
Sum of four test = 552 — 188 = 364
Now we can solve for the average of the other four test as shown below:
Average of four test = 364/4= 91
Answer:
Step-by-step explanation:
Vertically opposite angles are equal.
8y + 36 = 14y -24 Subtract 36 to both sides
8y = 14y - 24 - 36 Combine
8y = 14y - 60 Subtract 14y from both sides
8y - 14y = - 60
-6y = -60 Divide by - 6
-6y/-6 = -60/-6
y = 10
===========================
x +48 = 64 Subtract 48 from both sides
x +48 - 48 = 64-16
x = 16
Answer:
Part A:
C= cash Sue earns
H = hours Sue works
C is dependent upon H because C only changes when H is changed.
Part B:
(0,0)
(1,6)
Part C:
C=6H
Null hypothesis: 
Alternative hypothesis: 
The null is based on a recent study that 81% of the population (in this case senior citizens) takes at least one medication. The alternative hypothesis is basically the flip of the claim made in the null.
If Amelia wanted to know if the percentage was less than 81%, then the alternative would be p < 0.81
If Amelia wanted to know if the percentage was larger than 81%, then the alternative would be p > 0.81
However, she wants to know if the percentage is 81%.
