This ones a bit of a trick question, since whether the integers are even or odd doesn't really matter. What does matter, is that consecutive odd integers are 2 numbers apart (as are consecutive even integers).
So again, if the first of the odd integers is the variable n
the consecutive odd integers after it can be written as:
n+2 , n+4, etc...
So the sum of four consecutive odd integers can be written as:
sum = n + (n+2) + (n+4) + (n+6)
Simplify:
sum = 4n + 12
And finally rearrange to solve for n:
= n
This can also be written as:
- 3 = n
Whichever way you prefer.
Answer:
C.) The perimeter is doubled and the area is quadrupled.
Step-by-step explanation:
Original square: side = 4
Area = side^2 = 4^2 = 16 square units
Perimeter = 4 * side = 4 * 4 = 16 units
Larger square: side = 8
Area = side^2 = 8^2 = 64 square units
Perimeter = 4 * side = 4 * 8 = 32 units
Comparison of areas:
(larger square area)/(original square area) = 64/16 = 4
Comparison of perimeters:
(larger square perimeter)/(original square perimeter) = 32/16 = 2
Answer:
C.) The perimeter is doubled and the area is quadrupled.
Answer:
-1
Step-by-step explanation:
Answer:
36
Step-by-step explanation:
Because the bases are the same we can just subtract the exponents to get us 6² or 36.
Answer:
10
Step-by-step explanation:
For x=2, this is ...
5·2 = 10
