Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
he answer is 140 minutes to plant 14 saplings.
Step-by-step explanation:
30 divided by 3=10
so it takes 10 minutes to plant one sapling.
10x14=140 so this is how you get your answer. im 99% sure
The function based on the information will be S = -0.005D + 95.
<h3>How to illustrate the function?</h3>
It should be noted that d is the distance from the starting point while S is the speed.
The points given are (0 95)( 4000, 75).
Slope = (75 - 95)(4000 - 0)
= 0.005
The equation will be:
S = -0.005D + 95
Learn more about functions on:
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Answer:
Slope = 5
Point = (4, 2)
Step-by-step explanation: