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suter [353]
4 years ago
10

Find the values of the variables

Mathematics
1 answer:
blsea [12.9K]4 years ago
7 0
-12=2k means k is -6
-w^2 =-81 so w =9
2f=-14 so f=-7

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Express tan(23°−21°) in terms of tangents of 23∘and 21∘ You do NOT need to type in the degree symbol. Be sure to PREVIEW your an
Alja [10]

Answer:

  tan(23° -21°) = (tan(23°) -tan(21°))/(1 +tan(23°)tan(21°))

Step-by-step explanation:

The formula for the tangent of the difference of angles is ...

  tan(a-b) = (tan(a) -tan(b))/(1 +tan(a)tan(b))

Filling in the values a=23° and b=21°, you get the formula shown above.

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4 years ago
What is the approximate lateral area of the cylinder? Use 3.14 for r and round to
marusya05 [52]

Answer:

The answer is C) 678 cm2 :)

Step-by-step explanation:

3 0
3 years ago
Danny had 20 minutes to do a three-problem quiz. He spent 9 1/4 minutes on question A and 5 4/5 minutes on question B. How much
Travka [436]

Answer:

4 19/20

Step-by-step explanation:

9 1/4 + 5 4/5 = 15 1/20

20- 15 1/20 = 4  19/20

6 0
3 years ago
We would like to use the power series method to find the general solution to the differential equation d 2y dx2 − 4x dy dx + 12y
Feliz [49]

y=\displaystyle\sum_{n\ge0}a_nx^n

\dfrac{\mathrm dy}{\mathrm dx}=\displaystyle\sum_{n\ge1}na_nx^{n-1}\implies4x\dfrac{\mathrm dy}{\mathrm dx}=4\sum_{n\ge1}na_nx^n=4\sum_{n\ge0}na_nx^n

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}=\sum_{n\ge0}(n+2)(n+1)a_{n+2}x^n

Substituting into the ODE

\dfrac{\mathrm d^2y}{\mathrm dx^2}-4x\dfrac{\mathrm dy}{\mathrm dx}+12y=0

gives

\displaystyle\sum_{n\ge0}\bigg((n+2)(n+1)a_{n+2}-4na_n+12a_n\bigg)x^n=0

so that the coefficients of the series are given according to

\begin{cases}a_0=y(0)\\a_1=y'(0)\\a_{n+2}=\dfrac{4(n-3)a_n}{(n+2)(n+1)}&\text{for }n\ge0\end{cases}

We can shift the index in the recursive part of this definition to get

a_n=\dfrac{4(n-5)a_{n-2}}{n(n-1)}

for n\ge2. There's dependency between coefficients that are 2 indices apart, so we can consider 2 cases:

  • If n=2k, where k\ge0 is an integer, then

k=0\implies n=0\implies a_0=a_0

but since y(0)=0, we have a_0=0 and a_{2k}=0 for all k\ge0.

  • If n=2k+1, then

k=0\implies n=1\implies a_1=a_1

k=1\implies n=3\implies a_3=\dfrac{4(-2)a_1}{3\cdot2}=-\dfrac43a_1

k=2\implies n=5\implies a_5=0

and so a_{2k+1}=0 for all k\ge2. If y'(0)=1, we then have a_1=1 and a_3=-\dfrac43.

So the ODE has solution

y(x)=\displaystyle\sum_{k\ge0}(a_{2k}x^{2k}+a_{2k+1}x^{2k+1})\implies\boxed{y(x)=x-\dfrac43x^3}

8 0
3 years ago
The perimeter of a square is 176 centimeters. If the square is dilated by a scale factor of 0.25, what is the length of each sid
vovikov84 [41]

Answer:

It will be 11 for each side of the square

Step-by-step explanation:

Hope this Helped

6 0
3 years ago
Read 2 more answers
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