Question:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26.
What is the solution set of this problem?
Answer:
Step-by-step explanation:
Given
<em>Represent the number with x</em>
So:
Required
Determine the solution set
Open Both Brackets
Collect Like Terms
Multiply both sides by -1
Hence, the solution set is
Answer:
A. (x−2y)(y−3x)
=(x+−2y)(y+−3x)
=(x)(y)+(x)(−3x)+(−2y)(y)+(−2y)(−3x)
=xy−3x2−2y2+6xy
=−3x2+7xy−2y2
B. (2p+3)(p2−4p−7)
=(2p+3)(p2+−4p+−7)
=(2p)(p2)+(2p)(−4p)+(2p)(−7)+(3)(p2)+(3)(−4p)+(3)(−7)
=2p3−8p2−14p+3p2−12p−21
=2p3−5p2−26p−21
Hope it helps
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Thank you
Step-by-step explanation:
11. shape 1 => A = ½×17×10=85m²
shape 2=> A = 17×9 =153 m²
total area = 238 m²
12. shape 1 => A = 7×3= 21 m²
shape 2=> A = 3×2 = 6 m²
total area = 27 m²
A reclined chair or maybe a laptop
The first figure has 3 line segments.
the second figure has 3+3 =3*2 = 6 line segments
the third figure has 3+3+3 = 3*3 = 9 line segments
the fourth figure has 3+3+3+3=3*4=12 line segments...
so it is clear that:
the 20th figure has 3*20=60 line segments.
Answer: 60
