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777dan777 [17]
3 years ago
8

The perimeter of a square is 176 centimeters. If the square is dilated by a scale factor of 0.25, what is the length of each sid

e of the new square?
Mathematics
2 answers:
vovikov84 [41]3 years ago
6 0

Answer:

It will be 11 for each side of the square

Step-by-step explanation:

Hope this Helped

Talja [164]3 years ago
4 0

Answer:

Each side of the new square is 11

Step-by-step explanation:

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n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
3 years ago
Please help I’m having trouble understanding this question
Nikolay [14]

Answer: <1 = 26°

Step-by-step explanation:

given that:

• <ABD = 66°

• <2 = 14° + <1 (since ''more than' means we add)

• Find <1

Since it is obvious that <ABD is a sum of <1 and <2:

⇒ <ABD = <1 + <2

now we know that <2 is 14° more than <1 and that <ABD = 66°

⇒ 66° = <1 + (14° + <1)

⇒ 66° = <1 + 14° + <1

⇒ <1 = (66° - 14°) ÷ 2

⇒ <1 = 26° ...Answer...

hope that helps...

8 0
2 years ago
The rectangular prism has a base that is 3 \times 9\text{ m}3×9 m3, times, 9, start text, space, m, end text and a height of 2\t
lawyer [7]

Answer:

Volume of green house = 54 m³

Step-by-step explanation:

Given:

Base = 3m x 9m

Height of house = 2 m

Find:

Volume of green house

Computation:

Volume = lbh

Volume of green house = 3m x 9m x 2m

Volume of green house = 54 m³

8 0
3 years ago
.072 divided by 345.000 round to the nearest tenth
tino4ka555 [31]

Answer:

0.0

Step-by-step explanation:

Used a calculator

8 0
3 years ago
What is the range of the function f(x) = 3x2 + 6x - 8?
V125BC [204]

Answer:

  {y | y ≥ -11 }

Step-by-step explanation:

To answer a question like this, it is often helpful to graph the function or to rewrite it to vertex form.

  f(x) = 3x^2 +6x -8

  f(x) = 3(x^2 +2x) -8 . . . . factor the leading coefficient from x terms

  f(x) = 3(x^2 +2x +1) -8 -3(1) . . . . complete the square*

  f(x) = 3(x +1)^2 -11

The form of this equation tells you that the graph is a parabola that opens upward. Its vertex is (-1, -11), so the minimum value is -11. The range is the vertical extent of the function values, so goes upward from -11:

  y ≥ -11

_____

* Vertex form is ...

  f(x) = a(x -h)^2 +k

where "a" is the vertical scale factor and (h, k) is the vertex. When "a" is positive, the parabola opens upward; when it is negative, the parabola opens downward.

The square is completed by adding the square of half the x-coefficient inside parentheses, and subtracting the equivalent amount outside parentheses. Here, we had 2x inside parentheses, so we added (2/2)^2 = 1 inside and -3(1) outside, because "a" was 3.

_____

Brainly provides tools for properly rendering math symbols. 2-11 is not the same as ≥-11.

7 0
3 years ago
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