Depends on the number line my guy
Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.
![A'(x)=\frac{d}{dx}(80x-2x^{2})](https://tex.z-dn.net/?f=A%27%28x%29%3D%5Cfrac%7Bd%7D%7Bdx%7D%2880x-2x%5E%7B2%7D%29)
= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x = ![\frac{80}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B80%7D%7B4%7D)
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.
Answer:
a
Step-by-step explanation: