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Mandarinka [93]
3 years ago
6

?????????????????????????

Mathematics
2 answers:
diamong [38]3 years ago
5 0

Answer:

There are 0.00003 km in 3 cm

(Only 4 zeros after the decimal place)

Step-by-step explanation:

dolphi86 [110]3 years ago
3 0

Answer:

it should be B 0.00003

Step-by-step explanation:

Hope this helps have a nice day :)

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The English Alphabet has 20 letters more than one-fourth the number of letters in the Greek Alphabet. The English Alphabet has 2
KengaRu [80]

we are given that the English Aplhabet has 26 letters. we let g represent the number of letters in the Greek alphabet. From the statement given, English alphabet which is 26 = 20 + 1/4 *g. The expression which is similar to this is in option A. 1/4g + 20 = 26.

5 0
3 years ago
I will mark you. i need help fast thank you!
Ganezh [65]

Answer:

If I'm correct it should be the second one

Step-by-step explanation:

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5 0
3 years ago
you bought your friends a heart shaped pound of chocolate caramels. You anticipate each chocolate was 50 calories. Each chocolat
Wittaler [7]

There was 25.37% error in calculations.

Step-by-step explanation:

Given,

Anticipated calories = Approx value = 50 calories

Actual calories = Exact value = 67 calories

Percent error = \frac{|aprrox\ value-exact\ value|}{exact\ value}*100

Percent error = \frac{|50-67|}{67}*100

Percent error = \frac{|-17|}{67}*100=\frac{17}{67}*100

Percent error = \frac{1700}{67}

Percent error = 25.37%

There was 25.37% error in calculations.

Keywords: percent error, division

Learn more about division at:

  • brainly.com/question/10538663
  • brainly.com/question/10557275

#LearnwithBrainly

8 0
3 years ago
Add (-12x + 6) + (4x - 12).
yulyashka [42]

Step-by-step explanation:

it's obviously the equation is equals to zero,

-12x + 16 = 0

-12x = -16

-12. 12

like terms cancel each other to remaining with x

thus,

x = 4/3

<h2>AND</h2>

4x - 12 = 0

4x = 12

4. 4

like terms cancel each other to remaining (make x subject of the formula) with x

thus,

x = 3

6 0
2 years ago
How to integrate with steps:<br><br> (4x2-6)/(x+5)(x-2)(3x-1)
joja [24]

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx

You have a rational expression whose numerator's degree is smaller than the denominator's. This tells you you should consider a partial fraction decomposition. We want to rewrite the integrand in the form

\dfrac{4x^2-6}{(x+5)(x-2)(3x-1)}=\dfrac a{x+5}+\dfrac b{x-2}+\dfrac c{3x-1}

\implies4x^2-6=a(x-2)(3x-1)+b(x+5)(3x-1)+c(x+5)(x-2)

You can use the "cover-up" method here to easily solve for a,b,c. It involves fixing a value of x to make 2 of the 3 terms on the right side disappear and leaving a simple algebraic equation to solve for the remaining one.

  • If x=-5, then 94=112a\implies a=\dfrac{47}{56}
  • If x=2, then 10=35b\implies b=\dfrac27
  • If x=\dfrac13, then -\dfrac{50}9=-\dfrac{80}9c\implies c=\dfrac58

So the integral we want to compute is the same as

\displaystyle\frac{47}{56}\int\frac{\mathrm dx}{x+5}+\frac{10}{35}\int\frac{\mathrm dx}{x-2}+\frac58\int\frac{\mathrm dx}{3x-1}

and each integral here is trivial. We end up with

\displaystyle\int\frac{4x^2-6}{(x+5)(x-2)(3x-1)}\,\mathrm dx=\frac{47}{56}\ln|x+5|+\frac27\ln|x-2|+\frac5{24}\ln|3x-1|+C

which can be condensed as

\ln\left|(x+5)^{47/56}(x-2)^{2/7}(3x-1)^{5/24}\right|+C

7 0
3 years ago
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