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SSSSS [86.1K]
3 years ago
12

I want to know how to solve this equation

Mathematics
1 answer:
andre [41]3 years ago
8 0

9514 1404 393

Answer:

  B

Step-by-step explanation:

To find the inverse of y = f(x), solve the equation x = f(y) for y. For these functions, that's about the easiest way to do it.

  A. x = ∛(3y)   ⇒   x³ = 3y   ⇒   x³/3 = y . . . . . does not match g(x)

  B. x = 11y -4   ⇒   x +4 = 11y   ⇒   (x +4)/11 = y . . . . matches g(x)

  C. x = 3/y -10   ⇒   x +10 = 3/y   ⇒   3/(x+10) = y . . . . does not match g(x)

  D. x = y/12 +15   ⇒   x -15 = y/12   ⇒   12(x -15) = y . . . . does not match g(x)

_____

<em>Additional comment</em>

This is repeated application of the "solve for ..." process. In general, that process "undoes" what is "done" to the variable. The order of operations can tell you the order of the things that are done. The undoing is in the reverse order.

You need to be completely comfortable with the properties of equality (addition, subtraction, multiplication, division), and you need to understand the inverse functions of the functions we usually use: (powers, roots), (exponentials, logarithms), (trig functions, inverse trig functions). Of course, the inverse of addition is subtraction; the inverse of multiplication is division.

__

Above, we used a "shortcut" a couple of times:

  a = b/c   ⇒   c = b/a . . . . . equivalent to multiplying both sides by c/a.

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Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
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Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

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\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

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3 years ago
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Answer:

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Step-by-step explanation:

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