Answer:
A(t) = amount remaining in t years
 
       = A0ekt, where A0 is the initial amount and k is a constant to                     be determined.  
 
Since A(1690) = (1/2)A0 and A0 = 80, 
 
                 we have 40 = 80e1690k
 
                 1/2 = e1690k
 
                 ln(1/2) = 1690k
 
                 k = -0.0004
 
So, A(t) = 80e-0.0004t 
 
Therefore, A(430) = 80e-0.0004(430)
 
                            = 80e-0.172
 
                            ≈ 67.4 g
Step-by-step explanation:
 
        
             
        
        
        
What are the answer choices
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First one b ≤ 9 good luck
        
             
        
        
        
Answer:
the answer I got was 2878.3
 
        
             
        
        
        
1.301
Explanation:
Given:
 and
 and 
Note that from the properties of logarithms,





