Either way. The probability of hitting the circle is:
P(C)=Area of circle divided by area of square
P(W)=(area of square minus area of circle divided by area of square
P(C)=(πr^2)/s^2
P(W)=(s^2-πr^2)/s^2
...
Okay with know dimensions, r=1 (because r=d/2 and d=2 so r=1), s=11 we have:
P(inside circle)=π/121 (≈0.0259 or 2.6%)
P(outside circel)=(121-π)/121 (≈0.9744 or 97.4%)
Answer:
It decreases.
Step-by-step explanation:
10 / d
Lets say that it was 10 / 40, which is 10 divided by 40, 0.25.
Now, it has increased to twice the amount of that.
1 / 80, 10 divided by 80, which is 0.125
So, it decreases.
Answer:
![X = \left[\begin{array}{cccc}12&-24&8&16\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D12%26-24%268%2616%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
A matrix is given by
![A = \left[\begin{array}{cccc}6&-12&4&8\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%26-12%264%268%5Cend%7Barray%7D%5Cright%5D)
Now, we have to find the matrix X if 
⇒ X = 2A
Now, multiplication of a constant with a matrix means multiplication with that constant with all the terms of the matrix.
So, ![X = \left[\begin{array}{cccc}6 \times 2&-12 \times 2&4 \times 2&8 \times 2\end{array}\right]](https://tex.z-dn.net/?f=X%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D6%20%5Ctimes%202%26-12%20%5Ctimes%202%264%20%5Ctimes%202%268%20%5Ctimes%202%5Cend%7Barray%7D%5Cright%5D)
⇒ (Answer)
Answer: side
Step-by-step explanation:
