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insens350 [35]
2 years ago
7

Points E(-1, -2) and F(4, -2) are the vertices of a square. Give the coordinates of three possible pairs of points for the other

two vertices.
I already got the pairs:
(-1, 3), (4, 3)
(-1, -7), (4, -7)

I have no idea what to do for the third set of points.
Mathematics
1 answer:
777dan777 [17]2 years ago
5 0

The vertices of a square are its endpoints

The coordinates of the other pairs are: (-1, 3), (4, 3)  and (-1, -7), (4, -7)

The given parameters are:

\mathbf{E = (-1,-2)}

\mathbf{F = (4,-2)}

Calculate the distance EF

\mathbf{EF = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{EF = \sqrt{(-1 - 4)^2 + (-2 - -2)^2}}

\mathbf{EF = \sqrt{25}}

\mathbf{EF = 5}

Add 5 to the y-coordinates of E and F

\mathbf{C = (-1,-2+5)}

\mathbf{C = (-1,3)}

\mathbf{D = (4,-2+5)}

\mathbf{D = (4,3)}

Subtract 5 to the y-coordinates of E and F

\mathbf{C = (-1,-2-5)}

\mathbf{C = (-1,-7)}

\mathbf{D = (4,-2-5)}

\mathbf{D = (4,-7)}

Hence, the coordinates of the other pairs are: (-1, 3), (4, 3)  and (-1, -7), (4, -7)

There is no third pair

Read more about vertices at:

brainly.com/question/2791243

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