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Sunny_sXe [5.5K]
3 years ago
10

The following is a rhombus, find PQ

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

Answer:

76

Step-by-step explanation:

All sides of a rhombus are equal. Set NR equal to RQ, solving for x. When you find x, plug it back into either equation to find PQ.

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Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck
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\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}
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