Answer:
D
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = ( - 
, 
) and r = 
, thus
(x - (- ))² + (y - )² = ( )², that is
(x + )² + (y - )² = 
→ D
All you will have to do is put this inside of a graph and then see if it goes through the origin.
The width of the rectangle is 
unit
Step-by-step explanation:
The given is:
- A rectangles width is 4 less than its area
- Its length is 19 units
We need to find the width of the rectangle
Assume that the width of the rectangle is x units
∵ The area of the rectangle = length × width
∵ The width of the rectangle = x units
∵ The length of the rectangle = 19 units
∴ The area of the square = 19 × x = 19 x units²
∵ The width of the rectangle is 4 less than its area
- That means subtract 4 from the area to find the width
∴ x = 19 x - 4
- Subtract 19 x from both sides
∴ -18 x = -4
- Divide both sides by -18
∴ x = 
- Reduce the fraction by dividing up and down by -2
∴ x =
The width of the rectangle is unit
Learn more:
You can learn more about the rectangles in brainly.com/question/12919591
#LearnwithBrainly
A compass because youre just making two arcs
Answer:
1595 ft^2
Step-by-step explanation:
The answer is obtained by adding the areas of sectors of several circles.
1. Think of the rope being vertical going up from the corner where it is tied. It goes up along the 10-ft side. Now think of the length of the rope being a radius of a circle, rotate it counterclockwise until it is horizontal and is on top of the bottom 20-ft side. That area is 3/4 of a circle of radius 24.5 ft.
2. With the rope in this position, along the bottom 20-ft side, 4.5 ft of the rope stick out the right side of the barn. That amount if rope allows for a 1/4 circle of 4.5-ft radius on the right side of the barn.
3. With the rope in the position of 1. above, vertical and along the 10-ft left side, 14.5 ft of rope extend past the barn's 10-ft left wall. That extra 14.5 ft of rope are now the radius of a 1/4 circle along the upper 20-ft wall.
The area is the sum of the areas described above in numbers 1., 2., and 3.
total area = area 1 + area 2 + area 3
area of circle = (pi)r^2
total area = 3/4 * (pi)(24.5 ft)^2 + 1/4 * (pi)(4.5 ft)^2 + 1/4 * (pi)(14.5 ft)^2
total area = 1414.31 ft^2 + 15.90 ft^2 + 165.13 ft^2
total area = 1595.34 ft^2
