Answer:
a) Grade = 93, Standard score = 1.5
Grade = 62, Standard score = -1.6
b) Standard scores = 0.6, Grade = 84
Standard scores = 1.2, Grade = 90
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 78
Standard Deviation, σ = 10
Formula:

a) Grade = 93

Grade = 62

b) We have to find grades of student
Standard scores = 0.6

Grade = 84
Standard scores = 1.2

Grade = 90
Answer:
{
-
,
+
}
Step-by-step explanation:
ax² + bx + c = 0
= ( - b ±
) ÷ 2a
~~~~~~~~~~~
g(x) = 3x - 7
g²(x) = (3x - 7)²
g²(x) = 9x² - 42x + 49
g²(
) = 9(
)² - 42(
) + 49
9(
)² - 42(
) + 49 = 8
16k² - 56k + 41 = 0
a = 16 , b = - 56 , c = 41
D = b² - 4ac = ( - 56)² - 4(16)(41) = 512 =
= ( 56 + √
) ÷ 32 =
+
=
-
Answer:
−1
/2
qx+
1
/2
x-5
Step-by-step explanation:
Let's simplify step-by-step.
1
/2
x−7−
2q/
4
x−(−2)
=
1
/2
x+−7+
(−1/2)
qx+2
Combine Like Terms:
=
1
/2
x+−7+
(−1
/2
qx+2
=(
−1
/2
qx)+(
1
/2
x)+(−7+2)
=
−1
/2
qx+
1
2x+−5
Answer:
=
−1
/2
qx+
1
/2
x-5
HOPE THIS HELPS!!!!!! :)
<3333333333
No. Because sides JM and KL have different slopes from sides AD and BC .
The formula of a slope:

For AD:
We have the points A(2, -2) and D(1, -4). Substitute:

For JM:
We have the points J(4, -4) and M(2, -9). Substitute:


----------------------------------------
Another argument.
No. Because the MJ is not twice as long as AD.
The formula of the length of a segment:

The length of AD:

The length of MJ:


1: AAS 2: SAS 3: AAS 4: SAS 5: not congruent 6: SSS