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hammer [34]
3 years ago
9

Is quadrilateral jklm the result of a dilation of quadrilateral abcd by a scale factor of 2? why or why not?

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0

No. Because sides JM and KL have different slopes from sides AD and BC .

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

For AD:

We have the points A(2, -2) and D(1, -4). Substitute:

m=\dfrac{-4-(-2)}{1-2}=\dfrac{-2}{-1}=2

For JM:

We have the points J(4, -4) and M(2, -9). Substitute:

m=\dfrac{-9-(-4)}{2-4}=\dfrac{-5}{-2}=2.5

2\neq2.5

----------------------------------------

Another argument.

No. Because the MJ is not twice as long as AD.

The formula of the length of a segment:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AD:

|AD|=\sqrt{(1-2)^2+(-4-(-2))^2}=\sqrt{(-1)^2+(-2)^2}=\sqrt{1+4}=\sqrt5

The length of MJ:

|MJ|=\sqrt{(2-4)^2+(-9-(-4))^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}

\sqrt{29}\neq2\sqrt5

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Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

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The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, y_i

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Step-by-step explanation:

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