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Mnenie [13.5K]
2 years ago
5

What is the vertex of the parabola with the equation y=1/5x^2 + 2x - 8

Mathematics
1 answer:
bixtya [17]2 years ago
8 0

Answer:

(-5,-13)

Step-by-step explanation:

Find the vertex of the parabola y=1/5x^2+2x−8.  

In this equation a=15  and b = 2.  

x= -2/2(1/5) = -2/2/5 = -2/1 * 5/2 = -5

Substitute −5 into the equation y=1/5x^2+2x−8

y=1/5(−5)^2+2(−5)−8

y=5−10−8

y=−13

The vertex is (−5 , −13)

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To solve this system using elimination, one of the pairs of variable terms must cancel each other out. Their coefficients must be opposites of each other.

Multiply the top equation by 4.

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4(2x - y = 9)

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Add the equations together.

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+___________

11x - 0 = 22

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Substitute 2 for x into either of the original equations to find y.

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2(2) - y = 9

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Finally, check work by plugging x- and y-values into each original equation.

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Answer:

x = 2 and y = -5; (2, -5).

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2 years ago
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Assoli18 [71]

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Step-by-step explanation:

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Please help me i’ll appreciate it
yanalaym [24]

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Answer:

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You can pick a point, such as the vertex at (2, -3) on f(x) and see which of the transformations gives you a point on the graph of g(x).

You will find that g(x) represents a vertical scaling by a factor of 1/3, so ...

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7 0
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