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Mnenie [13.5K]
3 years ago
5

What is the vertex of the parabola with the equation y=1/5x^2 + 2x - 8

Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

(-5,-13)

Step-by-step explanation:

Find the vertex of the parabola y=1/5x^2+2x−8.  

In this equation a=15  and b = 2.  

x= -2/2(1/5) = -2/2/5 = -2/1 * 5/2 = -5

Substitute −5 into the equation y=1/5x^2+2x−8

y=1/5(−5)^2+2(−5)−8

y=5−10−8

y=−13

The vertex is (−5 , −13)

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