Work problems are solved by first figuring out how much of the job they can do in each hour. Shawn can do 1/4 of the job in an hour and Ellie can do 1/6 of the job in an hour. 1/6+1/4=2/12+3/12=5/12. This means that they can do 5/12 of the job an hour. This means that together they can do the job in 2 2/5 hours. The foreman is obviously wrong because first of all Shawn can do it alone in 4 hours, so with Ellie he will do it faster, and second of all 2 2/5<5. Hope this helped!
Answer:
1/36
Step-by-step explanation:
the chance of rolling a 2 on a 6-sided die is 1/6 and rolling a 5 on a 6-sided is also 1/6.
So, 1/6 * 1/6 = 1/36
Hope this is helpful
Use the Pythagorean theorem.
If x is a hypotenuse, then we have:

If x is a leg, then we have:

Answer: 
For this case we have the following expression:

For power properties we have:

Rewriting the exponents of the expression we have:



Using the cubic root we have:
![(\frac{1}{\sqrt[3]{8^2}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B8%5E2%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{64}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B64%7D%7D%20a%5E2%29%20%20%20)
![(\frac{1}{\sqrt[3]{4^3}} a^2)](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7B4%5E3%7D%7D%20a%5E2%29%20%20%20)
Simplifying the expression we have:

Answer:
The equivalent expression is given by:

Answer:
V=4
Step-by-step explanation:
Add it up