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levacccp [35]
3 years ago
7

How many calories will Jacob burn in 1 minute while roller-skating????fast plz

Mathematics
1 answer:
Marat540 [252]3 years ago
5 0

1 minute of P.E. usually burns 11 Kcals.

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A rectangular prism has a volume of 600 cubic inches.
choli [55]

Answer:

The length is 12 inches.

Step-by-step explanation:

The volume of a rectangular prism is given by:

V=LBH

It was given that; the rectangular prism has a volume of 600 cubic inches.

The height of the prism is 5 inches and the width is 10 inches.

We want to find the length of the rectangular prism.

We substitute V=600, H=5,and W=10 into the formula:

600=5×10×L

600=20L

L =  \frac{600}{50}

L = 12in

6 0
3 years ago
Which decimal is larger 36.36 or 36.63 PLEASE HELP!!
Alexeev081 [22]
36.36 is thirty-six and thirty-six hundredths.
36.63 is thirty-six and sixty-three hundredths.

The whole parts are the same. They are both 36.
The decimal parts are 0.63 and 0.36.
Sixty-three hundredths is greater than thirty-six hundredths.
Since 0.63 is greater than 0.36, 36.63 is greater.
7 0
3 years ago
A store has 300 televisions on order, and 80% are high definition, how many televisions on order are high difinition?
Brilliant_brown [7]

Answer:240

Step-by-step explanation:

300*80%=240

5 0
3 years ago
Read 2 more answers
Two couples (adam/brenda and carl/darlene) have bought tickets for four adjacent seats to see a musical. in how many ways can th
DochEvi [55]
One second I know this :)

7 0
3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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