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3 years ago

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The following dot plot shows the number of books each student checked out from the library last month. Each dot represents a dif

ferent student. Which of the following is a typical number of books one student checked out?

2 answers:

san4es73 [151]3 years ago

7 0

<h3>Answer: 8</h3>

This is the mode as it is the most frequent value with the highest tower of dots.

LuckyWell [14K]3 years ago

4 0

The answer is 8 my guy because I am big brain

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I need the help if you can please help me

alexdok [17]

Answer:13 days

Step-by-step explanation:

8.50 × 3 = 25.50

25.50 × 13 days = $331.50

4 0

3 years ago

Read 2 more answers

Para la construcción de una cabaña en el campo don Samuel compró 7,943 clavos hasta el momento ha utilizado 473 ¿cuantos clavos

Kazeer [188]

<u>Restando la cantidad utilizada de el total</u>, tiene-se que 7470 clavos le quedan.

----------------------

En total, para la construcción, Samuel compró 7,943 clavos.
De toda esta cantidad, 473 fueron utilizadas.
La cantidad de clavos que le quedan es la <u>subtracción da cantidad total por la utilizada</u>, o sea, 7943 restado de 473.

$7943 - 473 = 7470$

Le quedan 7470 clavos.

Un problema similar es dado en brainly.com/question/24554492

5 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

Which rational number is equivalent to 5.5?

Art [367]

Answer:

11/2

Step-by-step explanation:

Multiply by 2/2 to remove the decimal.

4 0

2 years ago

Read 2 more answers

The formula that describes an objects motion is given by s=ut+1/2at^2, where s is the distance traveled, u is the initial veloci

attashe74 [19]

We have the following equation:
s = ut + 1 / 2at ^ 2
Clear a for the equation:
1 / 2at ^ 2 = s-ut
at ^ 2 = 2s-2ut
a = 2s / t ^ 2-2ut / t ^ 2
Rewriting:
a = (2s-2ut) / (t ^ 2)
Answer:
An equation that represents a in terms of other variables is:
C. 2s-2ut / t ^ 2

6 0

3 years ago