$x^2=\dfrac{121}{196}\iff x=\pm\sqrt{\dfrac{121}{196}}\\\\x=-\dfrac{\sqrt{121}}{\sqrt{196}}\ \vee\ x=\dfrac{\sqrt{121}}{\sqrt{196}}\\\\\boxed{x=-\dfrac{11}{14}\ \vee\ x=\dfrac{11}{14}}\\\\\sqrt{a}=b\iff b^2=a\\\\\sqrt{121}=11\ \text{because}\ 11^2=121\\\\\sqrt{196}=14\ \text{because}\ 14^2=196$

7 0

4 years ago

Help me please thank you

lubasha [3.4K]

D..............................

6 0

3 years ago

A bag has 2 yellow, 7 red, and 1 green marble. What is the probability of picking a red marble, replacing it, and then picking a

Ulleksa [173]

Probability red+green

first pick(red) : 7/10
2nd pick( green) : 1/10

the answer maybe like this
prob : 7/10+1/10 = 8/10 =4/5

3 0

3 years ago