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gayaneshka [121]

2 years ago

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Mathematics

1 answer:

Mazyrski [523]2 years ago

3 0

Answer:

3.5972174e+13 could i get brainliest please?

Step-by-step explanation:

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Help please!!! can you show me how to do this??

IrinaK [193]

$\frac{3x - 2}{x^{2} - 2x - 3} - \frac{1}{x - 3} = \frac{3x -2}{(x + 1)(x - 3)} - \frac{1}{x - 3} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{1(x + 1)}{(x + 1)(x - 3)} = \frac{3x - 2}{(x + 1)(x - 3)} - \frac{x + 1}{(x + 1)(x - 3)} = \frac{2x - 3}{(x + 1)(x - 3)}$

5 0

3 years ago

6. a. Name a pair of equations that have exactly one point of intersection. How do you know?

True [87]

Answer:

A system of linear equations will have exactly one point of intersection, for example:

2x+y=5

-x+y=2

However, a system of linear equations with no solution will have no points of intersection, for example:

-4x+10y=6

2x-5y=3

Sorry about c. though I'm confused on how a pair of equations can have infinite points of intersection unless x or y equals all real numbers which could happen if x or y both equaled all real numbers maybe

And the point of interesection for the system of equations in the problem you attached as an image is (2,-1)

I attached a photo below, and one of how to graph it