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Andrews [41]
3 years ago
15

Tom and lorna sat the same test. Tom scored 70% on the test. Lorna scored 29 out of 40 marks. Who got a higher score? Justify yo

ur answer
Mathematics
1 answer:
Aleksandr [31]3 years ago
7 0

Answer:

Lorna

Step-by-step explanation:

29/40 = 72.5%

72.5% > 70% => Lorna got a higher score.

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75% of n is 45. n is what percent of 90?​
Law Incorporation [45]

Answer:

66.67%

Step-by-step explanation:

75 /100 = .75

.75n = 45

45/.75 = 60

60 is n

60/90 = .666667

.666667 * 100 = 66.67%

3 0
2 years ago
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This is very weird. How to find x and round that answer to the nearest tenth,
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3 years ago
Determine the equation of each line with the following properties:
iris [78.8K]

Answer:

a) y =2/3 x + 7.

b) x = -1

c) y = -4/5 x - 1/5

d) y = -3/2 x + 5/2.

Step-by-step explanation:

a) Intercept form y = mx + b where m = 2/3 and  b = 7

b) y can take any value but x is always -1.

c) Slope m = (-1-3)/ (1 - -4)

= -4/5

Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:

y - y1 = m(x - x1)

y - -1 = -4/5(x - 1)

y + 1 = -4/5x + 4/5

y = -4/5 x - 1/5

d)  The slope m of the line perpendicular to this line is:

-1 / 2/3

m = -3/2.

When x = -1 , y = 4 so using the slope intercept form of a line

y = mx + b

4 = -3/2 * -1 + b  where b = the y-intercept.

4 = 3/2 + b

b = 4 - 3/2 = 5/2.

The equation is  y = -3/2 x + 5/2.

3 0
3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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Add and subtract the following fractions. Remember to find the LCD first.
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11. 345,000

12. 128,000

13. 42.5

14. 39.6

15. $365.47; $365

16. $125.65; $126

4 0
3 years ago
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