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aalyn [17]
3 years ago
12

Question 2 of 10 If A PQR = ASTU, which statement must be true?

Mathematics
1 answer:
NISA [10]3 years ago
3 0

Answer:

PQ = ST

Step-by-step explanation:

..................

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4:50 P.M.

Step-by-step explanation:

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3 years ago
Can you solve 27,28,39,30,31,32,33,34?
kozerog [31]

Answer:

27. x^7

28. 4x^13

29. 1/f^4

30. x^5

31. 2x^14

32. (4y^3 x^2)^2

33. (2y/x)^6

Step-by-step explanation:

27. \:  \:  \frac{ {x}^{ - 1} }{ {x}^{ - 8} }  \\  \frac{ {x}^{8} }{ {x}^{1} }  \\  {x}^{8 - 1}   =  {x}^{7} \\

28. \:  \:  \:  \frac{ {52x}^{6} }{ {13x}^{ - 7} }  \\   \frac{ {52x}^{6}  {x}^{7} }{13}  \\  {4x}^{6 + 7}  =  {4x}^{13}

29. \:  \: {f}^{ - 3} ( {f}^{2} )( {f}^{ - 3} ) \\  {f}^{( - 3) +2 + ( - 3) }  \\  {f}^{ - 4}  \\  \frac{1}{ {f}^{4} }  \\

30. \:  \: \frac{ {x}^{ - 4} }{ {x}^{ - 9} } \\   \frac{ {x}^{9} }{ {x}^{4} }  \\  {x}^{9 - 4}  =  {x}^{5}

31. \:  \:  \frac{ {24x}^{6} }{ {12x}^{ - 8} }  \\  \frac{ {24x}^{6} {x}^{8}  }{12}  \\  {2x}^{6 + 8}  =  {2x}^{14}  \\

32. \:  \:  \frac{ {3x}^{2}  {y}^{ - 3} }{ {12x}^{6}  {y}^{3} }  \\  \frac{ {3x}^{2} }{ {12x}^{6} {y}^{3}  {y}^{3}  }  \\  \frac{ {x}^{2 - 6} }{ {4y}^{3 + 3} }  \\  \frac{ {x}^{ - 4} }{ {4y}^{6} }  \\  \frac{1}{ {4y}^{6}  {x}^{4} }  = \frac{1}{({ {4y}^{3} {x}^{2} ) }^{2} }

33. \:  \:  {( {2x}^{3}  {y}^{ - 3}) }^{ - 2}  \\ {2x}^{3 \times  - 2}  {y}^{ - 3 \times  - 2}  \\  {2x}^{ - 6}  {y}^{6}  \\  \frac{ {2y}^{6} }{ {x}^{6} }  \\  {( \frac{2y}{x} )}^{6} \\

4 0
2 years ago
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