Question

Suppose that telephone calls arriving at a switchboard follow a Poisson process with an average of 5 calls per minute. What is the probability up to a minute will elapse by the time 2 calls have come into the switchboard

Answer 1

Answer:

The correct answer is "0.0842".

Step-by-step explanation:

Given:

X = 5

By using the Poisson's distribution formula, we get

The probability will be:

⇒ $P(x=2)=\frac{\lambda^x.e^{-\lambda}}{x!}$

By substituting values, we get

                   $=\frac{(5)^2\times e^{-5}}{2!}$

                   $=\frac{25\times e^{-5}}{2!}$

                   $=0.0842$