The equation for the point-slope form is y - y1= m(x-x1), where m is the slope. Using the coordinates and slope given, y - 9 = -5(x-(-4)), which simplifies to
y - 9 = -5(x + 4)
<span>y=2(1/2)^x
</span>
x = 0; <span>y=2(1/2)^0 = 2(1) = 2
x = 1; </span><span>y=2(1/2)^1 = 2(1/2) = 1
answer is the last one.</span>
We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
The test statistic needed to evaluate the claim is t = -1.08.
Step-by-step explanation:
The test statistic is:
In which X is the sample mean, 
is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.
At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.
This means that 
Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.
This means that 
What is the test statistic needed to evaluate the claim?
The test statistic needed to evaluate the claim is t = -1.08.
