Answer:
r(t) and s(t) are parallel.
Step-by-step explanation:
Given that :
the lines represented by the vector equations are:
r(t)=⟨1−t,3+2t,−3t⟩
s(t)=⟨2t,−3−4t,3+6t⟩
The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.
NOTE:
Two lines will be parallel if 
here;

Thus;



∴

Hence, we can conclude that r(t) and s(t) are parallel.
If these are the missing choices:
A) Segments ST and PQ are parallel.
B) Angle P is congruent to itself due to the reflexive property.
C) RP is a transversal line passing ST and PQ.
<span>D) Angles RTS and RQP are congruent due to the Corresponding Angles Postulate.
</span>The fact that is not used to prove that PQR is similar to STR is <span>B) Angle P is congruent to itself due to the reflexive property.
</span>
Reflexive property in the given image is on Angle R not angle P.
Mx - y
5 times 3 - 8
15 - 8
=
7
Y=2x+2
(y=mx+c
m-slope/gradient
c-y intercept)
Step-by-step explanation:
the figure I've circled is similar to yhe figure shown because when we compare the measurements of the length and breadth of both rectangles, we can see that both the rectangles have the see me measurements, 3ft and 7ft. The only difference however, is that the figures have been rotated differently, the figure shown is kept vertically, on the other hand, the figure I've circled is rotated horizontally.
hope that helps...