Answer:
A. 2x, -4y, and 8
Step-by-step explanation:
If there is a minus sign in front of the 4 (-), add that to the expression. What you are just simply doing is separating the numbers up. For example:
12x - 8y + 4x
Now here, you have two of the same variables (x, y, etc). So, what you do is look at the last number that has the same variables, which is 4, and look at what the problem you will be solving, which is addition. So, very simply, you add then together!
12× + 4× = 16×
As you can see I kept the same variable. This is because, well, it is the same! Simply, just substitute in the 16× with the 8y. Now here is the tricky part, for some people. Do you see that there is a negative sign in front of the 8 (-)? Well! You have to substitute that in with the expression. No adding this or anything, just simply slide it next to the 16× because, we can not add nor subtract it with the 8y just because it has a different variable.
Your example answer would be: 16× - 8y
Hope this helps!
P.S. if you think this helped you at all, Brainliest me if ya want to. Have a great day!
First, do 100-14 to find out how much percent doesn't get the coupon= 85
then find 85% of 64= 54.4
finally, your answer is: 54.4
Answer:
the answer is 879
Step-by-step explanation:
1/3 ANS
hope this helps and i hope u ace it
Answer: The correct option is
(d) This is a divergent geometric series. The sum cannot be found.
Step-by-step explanation: The given infinite geometric series is
![S=\sum_{i=1}^{\infty}15(4)^{i-1}.](https://tex.z-dn.net/?f=S%3D%5Csum_%7Bi%3D1%7D%5E%7B%5Cinfty%7D15%284%29%5E%7Bi-1%7D.)
We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.
We have the D' Alembert's ratio test, states as follows:
Let,
is an infinite series, with complex coefficients
and we consider the following limit:
![L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.](https://tex.z-dn.net/?f=L%3D%5Clim_%7Bi%5Crightarrow%20%5Cinfty%7D%5Cdfrac%7Ba_%7Bi%2B1%7D%7D%7Ba_i%7D.)
Then, the series will be convergent if L < 1 and divergent if L > 1.
For the given series, we have
![a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.](https://tex.z-dn.net/?f=a_i%3D15%284%29%5E%7Bi-1%7D%2C%5C%5C%5C%5Ca_%7Bi%2B1%7D%3D15%284%29%5Ei.)
So, the limit is given by
![L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.](https://tex.z-dn.net/?f=L%5C%5C%5C%5C%5C%5C%3D%5Clim_%7Bi%5Crightarrow%20%5Cinfty%7D%5Cdfrac%7Ba_%7Bi%2B1%7D%7D%7Ba_i%7D%5C%5C%5C%5C%5C%5C%3D%5Clim_%7Bi%5Crightarrow%20%5Cinfty%7D%5Cdfrac%7B15%284%29%5Ei%7D%7B15%284%29%5E%7Bi-1%7D%7D%5C%5C%5C%5C%5C%5C%3D%5Clim_%7Bi%5Crightarrow%20%5Cinfty%7D%5Cdfrac%7B15%284%29%5Ei%7D%7B15%284%29%5E%7Bi%7D4%5E%7B-1%7D%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B4%5E%7B-1%7D%7D%5C%5C%5C%5C%3D4%3E1.)
Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.
Thuds, (d) is the correct option.