It is an odd-degree polynomial. Therefore...
As the coefficient is negative for x^9.
When x < 0 or x approaches negative infinity, y or f(x) will approach positive infinity.
When x approaches positive infinity, y or f(x) will approach negative infinity.
So it is the second and the third.
1x40
2x20
4x10
5x8
So it's 4 pairs
the new radius be to meet the client's need is 4.9 cm .
<u>Step-by-step explanation:</u>
Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:
Let we have two cylinders of volume with parameters as follows :
We know that volume of cylinder is , According to question volume of both cylinder is equal i.e
⇒
⇒
⇒
⇒
⇒ Putting all values
⇒
⇒
⇒
⇒
⇒
Therefore , the new radius be to meet the client's need is 4.9 cm .
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
D
Step-by-step explanation:
∠ABD = 0.5( arc AD + arc EC) = 0.5(131 + 53) = 0.5 × 184 = 92°
∠ABD and ∠ABC form a straight angle, thus
92 + ∠ABC = 180 ( subtract 92 from both sides )
∠ABC = 88° → D