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Julli [10]
3 years ago
15

Find the surface area of a cone with slant height of 9 inches and a radius of 3 inches. ANSWERS: 117 in2 81 in2 109 in2 113 in2

Mathematics
1 answer:
oee [108]3 years ago
7 0

Answer:117in2

Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words. Based on the Pythagorean theorem, find the missing length fo
Neporo4naja [7]

Answer: See below

Step-by-step explanation:

The Pythagorean Theorem is a²+b²=c². Since each problem gives us the length of a, b, or c, we can directly plug them into this equation and solve.

Triangle EFG

9²+b²=41²

81+b²=1681

b²=1600

b=√1600

b=40

----------------------------------------------------------------------

Triangle PQR

20²+21²=c²

400+441=c²

c²=841

c=√841

c=29

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Triangle XYZ

a²+24²=25²

a²+576=625

a²=49

a=√49

a=7

6 0
3 years ago
Explain why the exponents cannot be added in the product 12^3 x<br> 11^3.
sergij07 [2.7K]

Answer:

see explanation

Step-by-step explanation:

The exponents can only be added if the bases are the same

Here one base is 12 and the other is 11

So the rule of addition is not applicable.

4 0
2 years ago
Read 2 more answers
HELP ME <br> I WILL GIVE YOU BRAINLIEST
lana66690 [7]
76, because the graph shows how many visitors there are around 90 degrees
3 0
2 years ago
What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
A linear function contains the following points.
Softa [21]

Answer:

5

Step-by-step explanation:

its 5

8 0
3 years ago
Read 2 more answers
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