Answer: See below
Step-by-step explanation:
The Pythagorean Theorem is a²+b²=c². Since each problem gives us the length of a, b, or c, we can directly plug them into this equation and solve.
Triangle EFG
9²+b²=41²
81+b²=1681
b²=1600
b=√1600
b=40
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Triangle PQR
20²+21²=c²
400+441=c²
c²=841
c=√841
c=29
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Triangle XYZ
a²+24²=25²
a²+576=625
a²=49
a=√49
a=7
Answer:
see explanation
Step-by-step explanation:
The exponents can only be added if the bases are the same
Here one base is 12 and the other is 11
So the rule of addition is not applicable.
76, because the graph shows how many visitors there are around 90 degrees
So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Answer:
5
Step-by-step explanation:
its 5