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ser-zykov [4K]
3 years ago
11

Help ASAP please you will get brainly and 28 points

Mathematics
1 answer:
DiKsa [7]3 years ago
5 0
G
If it’s wrong I’m sorry but I’m pretty sure it’s G
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Simplify the expression (5 3i) (4-4i) a. 8i b. 9-i c. 9 i d. 9-7i
poizon [28]
The expression will be d. 9-7i
8 0
3 years ago
Which line has a constant proportionality of 4
Ne4ueva [31]

Answer:

Line A

Step-by-step explanation:

Line A has a constant of proportionality (slope) of 4.

3 0
2 years ago
The question is in the image! Please help if u can its due really soon
Leno4ka [110]

Answer:

Angle STR = 78°

Step-by-step explanation:

So, since line QS is a straight line, we know that it's 180°. We also know that angles QTR and STR both add up to 180°. That gives us an equation:

20x + 12 + 10x + 33 = 180

Combine like terms

30x + 45 = 180

Subtract 45 from both sides

30x = 135

Divide both sides by 30

x = 4.5

Now we know the value of x. We just need to plug it into angle STR's given value:

10(4.5) + 33 = angle STR

45 + 33 = angle STR

78° = angle STR

4 0
3 years ago
6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)
Yakvenalex [24]

Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots:  -3 and 5.  Most likely it is a quadratic (all of which have two roots).

Then f(x) = a(x + 3)(x - 5)

The graph goes through (1. 8):  Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

        a(4)(-4) = 8, or

            -16a = 8, which leads to a = -1/2.

Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

                                                        f(x) = (-1/2)(x^2 + 8x - 15)

4 0
3 years ago
. For each of these intervals, list all its elements or explain why it is empty. a) [a, a] b) [a, a) c) (a, a] d) (a, a) e) (a,
Eva8 [605]

Answer:

Elements are of the form

 (i) [a,a]=\{[x,y] : a\leq x\leq a, a\leq y\leq a; a\in \mathbb R\}

(ii) [a,b)=\{[x,y) :a\leq x

(iii)(a,a]=\{(x,y] :a

(iv)(a,a)=\{(x,y): a

(v) (a,b) where a>b=\{(x,y) : a>x>b,a>y>b;a>b,a,b \in \mathbb R\}

(vi) [a,b] where a>b=\{[x,y] : a\geq x\geq b,a\geq y\geq b;a>b,a,b \in \mathbb R\}

Step-by-step explanation:

Given intervals are,

(i) [a,a] (ii) [a,a) (iii) (a,a] (iv) (a,a) (v) (a,b) where a>b (vi)  [a,b] where a>b.

To show all its elements,

(i) [a,a]

Imply the set including aa from left as well as right side.

Its elements are of the form.

\{[a,a] : a\in \mathbb R\}=\{[0,0],[1, 1],[-1,-1],[2,2],[-2,-2],[3,3],[-3,-3],........\}

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a] represents singleton sets, and singleton sets are empty so is [a,a].

(ii) [a,a)

This means given interval containing a by left and exclude a by right.

Its elements are of the form.

[ 1, 1),[-1,-1),[2,2),[-2,-2),[3,3),[-3,-3),........

Since there is a singleton element a of real numbers withis the set, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  [a,a) represents singleton sets, and singleton sets are empty so is [a.a).

(iii) (a,a]

It means the interval not taking a by left and include a by right.

Its elements are of the form.

( 1, 1],(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Since there is a singleton element a of real numbers, this set is empty.

Because there is no increment so if a\in \mathbb R then the set  (a,a] represents singleton sets, and singleton sets are empty so is (a,a].

(iv) (a,a)

Means given set excluding a by left as well as right.

Since there is a singleton element a of real numbers, this set is empty.

Its elements are of the form.

( 1, 1),(-1,-1],(2,2],(-2,-2],(3,3],(-3,-3],........

Because there is no increment so if a\in \mathbb R then the set  (a,a) represents singleton sets, and singleton sets are empty, so is (a,a).

(v) (a,b) where a>b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which not take x and y by any side of the interval.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

(a,b)=\{(5,0),(5,1),(5,2).....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

(vi) [a,b] where a\leq b.

Which indicate the interval containing a, b such that increment of x is always greater than increment of y which include both x and y.

That is the graph is bounded by value of a and it contains elements like it we fixed a=5 then,

[a,b]=\{[5,0],[5,1],[5,2].....\} e.t.c

So this set is connected and we know singletons are connected in \mathbb R. Hence given set is empty.

8 0
3 years ago
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