What is cos 60°?

Simplify y^-3 a.3/y b.1/y^3 c.-3y d.-1/y^3

nignag [31]

Answer:

b. $\frac{1}{y^3}$

Step-by-step explanation:

Here we are given $y^{-3}$ and are asked to simplify it. We are going to apply the law of exponents which says that

$a^{-n}=\frac{1}{a^n}$

Hence applying this rule in our problem we get, where a=y and n=3

$y^{-3}=\frac{1}{y^3}$

Hence our C) Option is correct

3 0

3 years ago

What is the sum of ? I will put a pic if the answer is correct ill mark brainlist

olga2289 [7]

$\text{The sum of } 1\frac{7}{10} \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}$

Solution:

Given that we have to find the sum of $1\frac{7}{10} \text{ and } 3\frac{3}{5}$

Let us first convert the mixed fractions to improper fractions

Multiply the whole number part by the fraction's denominator.

Add that to the numerator.

Then write the result on top of the denominator

Therefore,

$1\frac{7}{10} = \frac{10 \times 1 + 7}{10} = \frac{10+7}{10} = \frac{17}{10}\\\\3\frac{3}{5} = \frac{5 \times 3 + 3}{5} = \frac{18}{5}$

Now we can add both the fractions

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18}{5}$

Make the denominators same

$1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}$