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Murrr4er [49]
3 years ago
9

Help pls!! What is the perimeter of triangle FBD?

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

<em>46</em>

Step-by-step explanation:

AC = 2FD

CE = 2BF

AE = 2BD

2FD + 2BF + 2BD = <u><em>2(FD + BF + BD) = AC + CE + AE</em></u>

2P_{FBD} = P_{ACE} ⇒ P_{FBD} = \frac{1}{2} P_{ACE}

P_{FBD} = 92 ÷ 2 =<em> 46 units</em>

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Answer:

The diameter of the circle O is <em>12 units</em>

Step-by-step explanation:

There is no data in the image provided. To better help you, I'm assuming we have an arbitrary value of  

BC=6\sqrt{2}

and the triangle B0C is right

<u>Relations in the Circle</u>

The diameter (D) is twice the radius (r) and the radius is the distance measured from the center of the circle to any point of the circumference.  

Since the triangle B0C has a right angle, BD is the hypotenuse and 0B=0C=r

Applying Pythagoras's theorem:

BC^2=r^2+r^2=2r^2

Thus we have

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vodomira [7]

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3 0
2 years ago
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Step-by-step explanation

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Step-by-step explanation:

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Step-by-step explanation:

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