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Studentka2010 [4]
3 years ago
9

Find the volume of the solid. 4km, 8km, and 12km

Mathematics
1 answer:
ahrayia [7]3 years ago
8 0
Bussneshxhdbdbdbdbdhddhxhhdhdhdhdhdhdbdbdbddbbdndbdbdbdbdbdbd
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In the image, the distance from the swings to the slide is 35
Nikitich [7]
The Pythagorean theorem is a^2+b^2=c^2 where a and b are legs and c is the hypotenuse(longest side). you haven’t put a picture so I don’t know where 35 is a leg or the hypotenuse, but all you have to do is square the 2 shorter sides and add them and set it equal to the square of the longer side. You can do it!
5 0
3 years ago
I honestly don’t understand this at all can you help?
blondinia [14]
A. the first box is 7 
    the second box is 2
    the third box is 100 
    the fourth box is 6.5
    RULE: times 3 + 2
b. the first box is 45/2
    the second box is -0.75
    the third box is 0
    the fourth box is 2.75 
    RULE: times 5/2
c. the first box is 1 1/2
    the second box is 6
    the third box is -4
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6 0
3 years ago
Read 2 more answers
A city has a population of 230,000 people. suppose that each year the population grows by 3.5% . what will the population be aft
Georgia [21]
230000÷3.5%=6571%
6571%*15=9857%(be after 15 years)
5 0
3 years ago
A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

Volume=\frac{1}{2} (b_{1}+4+2x)h X H

Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0
3 years ago
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1083 and x=550 who said
Zigmanuir [339]

Step-by-step explanation:

p = x / n

p = 550 / 1083

p = 0.5078

5 0
3 years ago
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