What is (12-2i) (5+3i) multiplied?

1 answer:

Ilya [14]3 years ago

5 0

= 12*5 + 12*3i - 5*2i - 6i^2 (remember that i^2 = -1) so:-

= 60 +26i - 6*(-1)

= 60 + 26i + 6

= 66 + 26i

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