Answer:
It is hard to see the numbers.
But I am pretty sure it is 6x+6.
Step-by-step explanation:
Hope this helps! :D
Answer:
The larger integer is 
.
Step-by-step explanation:
Given: Two times the smaller of two consecutive integers is equal to 
more than the larger.
To find: The larger integer.
Solution:
Let the two consecutive integers be 
and 
, where the smaller integer is and larger integer is .
Now, according to question.
Two times the smaller integer 
more than the larger integer.
So, the smaller integer is 
, and the larger integer is 
Hence, the larger integer is 
Step-by-step explanation:
they are similar by AA .
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Answer:
(f + g)(x) = 3x² + (7/3)x - 8
Step-by-step explanation:
To find (f + g)(x), you need to add both the f(x) and g(x) equations together.
f(x) = x/3 - 2 ..... which is equal to ... f(x) = (1/3)x - 2
g(x) = 3x² + 2x - 6
(f + g)(x) = ((1/3)x - 2) + (3x² + 2x - 6) <----- Add both equations
(f + g)(x) = 3x² + (1/3)x + 2x - 2 - 6 <----- Rearrange (2 = 6/3)
(f + g)(x) = 3x² + (7/3)x - 8 <----- Simplify similar terms
Equation 1: y = -2x + 1
Equation 2: y = 2x - 3
Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.
-2x + 1 = 2x - 3
1 = 4x - 3
4 = 4x
x = 1
Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.
y = 2x - 3
y = 2(1) - 3
y = 2 - 3
y = -1
Hope this helps!! :)
