Can I get the measures of the figures? I’d be glad to help :))
AnsAnswerwer:
sorry i can't help without the picture of the problem
Step-by-step explanation:
(y-k)²=4p(x-h)
(h,k) is vertex
and since we got the y term squred, it is facing left or right
when p is positive, then focus is to right of veretx
p is distance from focus to vertex and from vertex to dirextix
y²=-x
(y-0)²=4(-1/4)(x-0)
vertex is (0,0)
p is negative so then focus to left of vertex
so the focus is (-1/4,0)
dirextix is x=1/4
Answer:
(4) y=(x-3)²-4
I dont have much evidence to give