Answer:
y=-8/3x-11 is the equation of the line and the value of y
Step-by-step explanation:
Use point slope form m = y-y1/x-x1, or y-y1=m(x-x1)
Find the slope from the two points (-6,5) and (-3,-3)
m = y2-y1/x2-x1 = -3-5/-3+6 = -8/3
use one point say (-6,5) that passes through the line and the slope to form the equation y-5=-8/3(x+6) rearrange y= -8/3(x+6)+5
y=-8/3x - 48/3 +5 = -8/3x-16+5 = -8/3x-11
