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Contact [7]
3 years ago
9

Complete the equation of the line through (-6,5) and (-3,-3)

Mathematics
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

y=-8/3x-11 is the equation of the line and the value of y

Step-by-step explanation:

Use point slope form m = y-y1/x-x1, or y-y1=m(x-x1)

Find the slope from the two points (-6,5) and (-3,-3)

m = y2-y1/x2-x1 = -3-5/-3+6 = -8/3

use one point say (-6,5) that passes through the line and the slope to form the equation y-5=-8/3(x+6) rearrange y= -8/3(x+6)+5

y=-8/3x - 48/3 +5 = -8/3x-16+5 = -8/3x-11

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tensa zangetsu [6.8K]
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
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Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
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